Question 145906
Solve for x:
{{{x^2-4x = 6}}} Complete the square in x by adding the square of half the x-coefficient to both sides of the equation. That's {{{(-4/2)^2 = 4}}}
{{{x^2-4x+4 = 6+4}}} Factor the left side and simplify the right side.
{{{(x-2)^2 = 10}}} Take the square root of both sides.
{{{(x-2) = sqrt(10)}}} or {{{(x-2) = -sqrt(10)}}} Add 2 to both sides of each solution.
{{{x = 2+sqrt(10)}}} or {{{x = 2-sqrt(10)}}}