<PRE><B>Question 145804</B>
call the bales (in order of increasing weight) A, B, C, D, E


the lowest and highest weights are the 2 lightest and 2 heaviest respectively
__ A+B=110 __ D+E=121


the 2nd lowest is the lightest bale with the middle bale __ A+C=112


the 2nd highest is the heaviest bale with the middle bale __ C+E=120


every bale is weighed with each of the other 4 bales, so every bale is weighed 4 times
__ this means that the sum of the weights is 4 times the sum of the weights of the individual bales


A+B+C+D+E=(110+112+113+114+115+116+117+118+120+121)/4 __ A+B+C+D+E=289


substituting __ 110+C+121=289 __ C=58


substituting __ A+58=112 __ A=54


substituting __ 54+B=110 __ B=56


substituting __ 58+E=120 __ E=62


substituting __ D+62=121 __ D=59</PRE>