<PRE><B>Question 145727</B>
find the vertex, axis of symmetry and graph: f(x)= -x^2-6x+3, in the back of my math book it says the vertex is (-3,12) i keep getting (-3,-6) 
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Vertex occurs where x = -b/2a = 6/-2 = -3
f(-3) = -(-3)^2-6(-3)+3 = -9+18+3 = 12
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Vertex at (-3,12)
Axis at x = -3
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{{{graph(400,300,-10,10,-10,20,-x^2-6x+3)}}}
Cheers,
Stan H.
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