Question 145713
There is a small error in step 4:
3^x+4=5^x-1 
(x+4)log3=(x-1)log5 
xlog3+4log3=xlog5-1log5 
4log3+1log5=xlog3-xlog5 SHOULD BE 4log3 + 1 log 5= xlog5 - x log 3


Next, factor the x from the right side of the equation:

4log3 + 1 log 5= x(log5 -  log 3)


Last, divide both sides by (log5 - log3)


{{{(4log3 + 1 log 5)/(log5 - log 3)= (x(log5 -  log 3))/(log5 - log3) }}}

{{{x=(4log3 + 1 log 5)/(log5 - log 3) }}}


Can you use a calculator to calculate this??  I get x=11.75.


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R^2