Question 145701
To convert the general equation {{{log(b,(x))=y}}} to exponential form, simply rewrite the equation as {{{b^y=x}}}


a) So {{{log(3,(27))=3}}} becomes {{{3^3=27}}}



b) So {{{log(e,(1))=0}}} becomes {{{e^0=1}}}



c) So {{{log(125,(25))=2/3}}} becomes {{{125^(2/3)=25}}}



note: you can use a calculator to verify your answers.