Question 145700
To convert into logarithmic form, simply rewrite the general equation {{{b^x=y}}} to get {{{log(b,(y))=x}}}


a) {{{16^(3/2)=64}}} becomes {{{log(16,(64))=3/2}}}



b) {{{e^(x)=5}}} becomes {{{log(e,(5))=x}}} which also looks like {{{ln(5)=x}}}