Question 145677


{{{3x-4y=80}}} Start with the given equation



{{{-4y=80-3x}}}  Subtract {{{3 x}}} from both sides



{{{-4y=-3x+80}}} Rearrange the equation



{{{y=(-3x+80)/(-4)}}} Divide both sides by {{{-4}}}



{{{y=(-3/-4)x+(80)/(-4)}}} Break up the fraction



{{{y=(3/4)x-20}}} Reduce




So the equation is now in slope-intercept form ({{{y=mx+b}}}) where the slope is {{{m=3/4}}} and the y-intercept is {{{b=-20}}}