Question 145575
The numerator:
(b^2 +5b +6)/ 3 bc = (b^2 + 3b + 2b + 6)/3bc
                   = (b+2)(b+3)/3bc
The denominator:
(b^2 -9) / 6bc = (b-3)(b+3) / 6bc
so, the expression is:

(((b+2)(b+3)/3bc)/((b+3)(b-3)/6bc)) = (b+2)/2(b-3).
So the answer is A.