Question 145507
{{{(2/3)y+k=j}}} Start with the given equation



{{{(2/3)y=j-k}}} Subtract k from both sides



{{{cross((3/2)(2/3))y=(3/2)(j-k)}}} Multiply both sides by {{{3/2}}}




So our answer is {{{y=(3/2)(j-k)}}}