Question 145402
{{{y=(1/2)x-3}}} Start with the first equation



{{{-2x-2=(1/2)x-3}}} Plug in {{{y=-2x-2}}}



{{{(2)(-2x-2)=(2)((1/cross(2))x-3)}}} Multiply both sides by the LCM of 2. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{-4x-4=x-6}}} Distribute and multiply the LCM to each side




{{{-4x=x-6+4}}}Add 4 to both sides



{{{-4x-x=-6+4}}} Subtract x from both sides



{{{-5x=-6+4}}} Combine like terms on the left side



{{{-5x=-2}}} Combine like terms on the right side



{{{x=(-2)/(-5)}}} Divide both sides by -5 to isolate x




{{{x=2/5}}} Reduce. This is the first part of our answer.



{{{y=(1/2)x-3}}} Go back to the first equation



{{{y=(1/2)(2/5)-3}}} Plug in {{{x=2/5}}}



{{{y=1/5-3}}} Multiply



{{{y=-14/5}}} Combine like terms




So our answer is {{{x=2/5}}} and {{{y=-14/5}}}