Question 145242
1.  {{{y=e^4}}}
{{{ln y = ln e^4  }}}


{{{ln e^x = x}}}
{{{ln y = ln e^4 =4 }}}


2.  Find the rate of change of y, when y=30 + 4x, over the interal x=2 to x=4.


Rate of change of y is actually the "slope" of the curve at a given point.  In this case, you have a straight line with slope 4.  This is the rate of change.  Final answer = 4.


R^2