Question 145181
4x+2y=4  <<--equation 1
3x+y=4   <<--equation 2
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Let's start by solving equation 2 for y:
3x+y=4
y=4-3x
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Now, using equation 1, substitute y for the value above:
4x+2y=4
4x+2(4-3x)=4
4x+8-6x=4
8-2x=4
-2x=-4
x=2
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To find y, substitute x for 2 into either equation -- I'll pick equation 2:
3x+y=4
3(2)+y=4
6+y=4
y=-2
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(x,y)=(2,-2)