Question 145180
What pops out right away is I should multiply the 1st equation by {{{2}}}
and then it will look like the 2nd equation
{{{x = (7/2)y + 9}}}
{{{2x = 7y + 18}}}
Now add {{{7y}}} to both sides of the 2nd equation
{{{2x - 7y = 18}}}
{{{2x = 7y + 18}}}
Both equations are identical, so the answer is
that the equations are dependent