Question 145132
Solve:
{{{y^2 = 16}}} Take the square root of both sides.
{{{sqrt(y^2) = sqrt(16)}}}
{{{y = 4}}} or {{{y = -4}}}

{{{(x-3)^2 = 25}}} Take the square root of both sides.
{{{sqrt((x-3)^2) = sqrt(25)}}}
{{{x-3 = 5}}} or {{{x-3 = -5}}} Add 3 to both sides in each case.
{{{x = 3+5}}} or {{{x = 3-5}}}
{{{x = 8}}} or {{{x = -2}}}