Question 145133
Both of your equations are in the form {{{ax^2+bx+c=0}}}.  For example, for the first one: {{{a=1}}}, {{{b=6}}}, and {{{c=1}}}.


Just plug the values for {{{a}}}, {{{b}}}, and {{{c}}} into:


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 


and then do the arithmetic.  Notice the 'plus or minus' sign, meaning that you will have two solutions for each equation.


Also, check the number under the radical for perfect square factors, and take them out.  For example {{{sqrt(8)=sqrt(4*2)=sqrt(4)sqrt(2)=2sqrt(2)}}}


Also, note that the coefficient on the 1st degree term in your second equation includes the minus sign.