Question 145102
{{{-x^2+2x}}}=8
{{{-(x^2-2x)}}}=8    taking minus sign common
 {{{x^2-2x}}}=-8   dividing by -1 both sides
{{{x^2-2x+8}}}=0
{{{x^2-4x+2x-8}}}=0     breaking middle term
{{{(x-4)*(x+2)}}}=0
 x=4 or x=-2