Question 145003
From {{{4x^2+7x+4}}} we can see that {{{a=4}}}, {{{b=7}}}, and {{{c=4}}}



{{{D=b^2-4ac}}} Start with the discriminant formula



{{{D=(7)^2-4(4)(4)}}} Plug in {{{a=4}}}, {{{b=7}}}, and {{{c=4}}}



{{{D=49-4(4)(4)}}} Square {{{7}}} to get {{{49}}}



{{{D=49-64}}} Multiply {{{4(4)(4)}}} to get {{{(16)(4)=64}}}



{{{D=-15}}} Subtract {{{64}}} from {{{49}}} to get {{{-15}}}


So the discriminant is {{{D=-15}}}