Question 144909
A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108in2. What are the dimensions of the photo?
:
Let x = the width of the photo
:
It says,"A photo is 3 inches longer that it is wide. ", therefore:
(x+3) = the length of the photo
:
The dimensions of the whole thing: (x+3)+ 4, x + 4, which is
(x+7) by (x+4)
:
Given the area of the whole thing:
(x+7)(x+4) = 108
FOIL
x^2 + 11x + 28 - 108 = 0
:
x^2 + 11x - 80 = 0
Factor
(x+16)(x-5) = 0
The positive solution:
x = 5" is the width of the photo
and
5 + 3 = 8" is the length of the photo
:
:
Check solution)
(8+4) * (5+4) = 108