Question 144523
first take these values equal  {{{(p+2)/2}}}={{{3(p-2)/4}}}
Now by cross multiplication
4(p+2)=6(p-2)
4p+8=6p-12
6p-4p-12-8=0
2p-20=0
p-10=0  dividing by 2
this is an equation of a line .In order to draw a graph we must have two variables connected by either equality or inequality sign.but if we consider a variable like q and take its values on vertical line then graph of above equation will be a vertical line otherwise a horizontal line be formed.as first value is greater than second value so p-10>0.hence graph contains the set of all points on the left of this line.