Question 144829

{{{D=b^2-4ac}}} Start with the discriminant formula



From {{{m^2+m+1}}} we can see that {{{a=1}}}, {{{b=1}}}, and {{{c=1}}}



{{{D=(1)^2-4(1)(1)}}} Plug in {{{a=1}}}, {{{b=1}}}, and {{{c=1}}}



{{{D=1-4(1)(1)}}} Square {{{1}}} to get {{{1}}}



{{{D=1-4}}} Multiply {{{4(1)(1)}}} to get {{{(4)(1)=4}}}



{{{D=-3}}} Subtract {{{4}}} from {{{1}}} to get {{{-3}}}



Since the discriminant is less than zero, this means that there are two complex solutions