Question 144830
First odd integer: {{{x}}}
Second consecutive odd integer: {{{x+2}}}
Third consecutive odd integer: {{{x+4}}}


The sum of the first and second: {{{x + (x + 2)=2x +2}}}
4 times the sum of the 1st and 2nd: {{{4(2x+2)=8x+8}}}


7 times the third: {{{7(x+4)=7x+28}}}
17 more than 7 times the 3rd: {{{7x+28+17=7x+45}}}


So: {{{8x+8=7x+45}}}.  Solve this for x and verify that x is odd.


The sum of the three integers is: {{{x + (x+2) + (x+4)=3x+6}}}.  Take the solution you found above, multiply by 3 and then add 6 to get your final answer.