Question 144805
Kepler's Third Law:

{{{T^2/R^3}}}

Given:
{{{R =0.723}}} Astronomical Units

{{{T^2/R^3=1}}}………{{{1}}} stands for one complete orbit of the sun

{{{T^2= (0.723 )^3}}}

{{{T^2= 0.377933067}}}

{{{T= sqrt(0.377933067)}}}

{{{T=0.61476261028139959578935214317083}}} Earth years

……………which is {{{0.61476261028139959578935214317083*365=224.38835275271085246311353225705}}} Earth days

Or approximately
{{{T=0.615}}} Earth years……………which is {{{0.615*365=224.475}}} Earth days