Question 144772
let the numbers be: 2n+1, 2n+3

Then, (2n+1)(2n+3)=143
4n^2+8n+3=143
4n^2+8n-140=0
n^2+2n-35=0
(n+7)(n-5)=0

So n=-7 or n=5. Now, we probably only want the positive solution here, so n=5.

And the numbers are:
11 and 13.

11*13=143.