Question 144731


{{{6x^2-42x+72=0}}} Start with the given equation


{{{6(x-4)(x-3)=0}}} Factor the left side 



Now set each factor equal to zero:

{{{x-4=0}}} or  {{{x-3=0}}} 


{{{x=4}}} or  {{{x=3}}}    Now solve for x in each case



So our answers are


 {{{x=4}}} or  {{{x=3}}}