Question 144590
Factor Completely
252c^2 + 588cg + 343g^2
:
Try a some low prime numbers to see if any will go evenly into all 3 numbers
Dividing each by 7 we get:
7(36c^2 + 84cg + 49g^2)
:
Note that the 1st and last coefficients are perfect squares, a clue that this may be factored to:
7(6c + 7g)(6c + 7g)