Question 144502
6 - z 3z - 7
----- - ------- =
z - 2 2 - z 
:
{{{(6-z)/(z-2)}}} - {{{(3z-7)/(2-z)}}}
:
Note that if we can multiply the 2nd denominator by -1, changes the signs inside the brackets
{{{(6-z)/(z-2)}}} - {{{(3z-7)/(-1(z-2))}}}
:
dividing by -1 changes the sign of the fraction
{{{(6-z)/(z-2)}}} + {{{(3z-7)/(z-2)}}}
:
The denominators are the same:
{{{(6 - z + 3z - 7)/(z-2)}}} = {{{(2z-1)/(z-2)}}}