Question 144376
Factor it first:

f(x)=(x+2)^2
The x-coordinate of the vertex will be where this function is valued least because the coefficient of x^2 is positive. That is, where (x+2)=0. That is x=-2. f(-2)=0. (-2,0) is the vertex.

Now, we know that x-intercepts are when the function is equal to 0. Thus we already found the only one: (-2,0)

For a y-intercept, we will set x=0. This gives f(0)=4. Therefore (0,4) is the y-intercept. This function will be symmetric about the line x=-2 (by definition). This is enough information to produce the following graph:

{{{graph( 300, 200, -5, 5, -5, 5, (x+2)^2 )}}}