Question 144334
{{{ln(4x-2)=ln(8x)}}} Start with the given equation


Since the logs have the same base, this means that the arguments are equal. So 


{{{4x-2=8x}}} Set the inner arguments equal to one another.



{{{4x=8x+2}}}Add 2 to both sides



{{{4x-8x=+2}}} Subtract 8x from both sides



{{{-4x=2}}} Combine like terms on the left side



{{{x=(2)/(-4)}}} Divide both sides by -4 to isolate x




{{{x=-1/2}}} Reduce



So the possible answer is {{{x=-1/2}}} 



However, since you cannot take the log of negative number, this means that {{{x=-1/2}}} is not a real solution. So there are no solutions.