Question 144239
{{{(1/12)u-1/36+(1/2)u=1/2+u}}} Start with the given equation




{{{(36)((1/cross(12))u-1/cross(36)+(1/cross(2))u)=(36)(1/cross(2)+u)}}} Multiply both sides by the LCM of 36. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{3u-1+18u=18+36u}}} Distribute and multiply the LCM to each side




{{{21u-1=18+36u}}} Combine like terms on the left side



{{{21u=18+36u+1}}}Add 1 to both sides



{{{21u-36u=18+1}}} Subtract 36u from both sides



{{{-15u=18+1}}} Combine like terms on the left side



{{{-15u=19}}} Combine like terms on the right side



{{{u=(19)/(-15)}}} Divide both sides by -15 to isolate u




{{{u=-19/15}}} Reduce


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Answer:

So our answer is {{{u=-19/15}}}  (which is approximately {{{u=-1.2667}}} in decimal form)