Question 144234
Let {{{W=2x-5}}}



Since the length is "10 feet longer than the width", this means that {{{L=W+10=(2x-5)+10=2x+5}}}



So to find the area, use this formula


{{{A=L*W}}}



{{{A=(2x-5)(2x+5)}}} Plug in {{{W=2x-5}}} and {{{L=2x+5}}}



{{{A=4x^2+10x-10x-25}}} Foil



{{{A=4x^2-25}}} Combine like terms



So the area is {{{A=4x^2-25}}}