Question 144203
Solve 
log2(x+5)+log2(x-1)=4 
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log2[(x+5)(x-1)] = 4
[(x+5)(x-1)] = 2^4
x^2+4x-5 = 16
x^2 + 4x -21 = 0
(x+7)(x-3) = 0
Positive solution:
x = 3
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Cheers,
Stan H.