Question 144115
An astronaut on the moon tosses a ball upwards; when will the ball initially be 35 feet above the lunar surface if the ball's height (feet) follow:
h(t) = -2.6t^2 + 32.1t + 5.5, and t is in seconds from release? 
a. 1 second
b. 2 seconds
c. 1/2 seconds
d. 13.2 seconds 
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EQUATION:
-2.6t^2+32.1t + 5.5 = 35

-2.6t^2+32.1t-29.5 = 0

Since the coefficients add up to zero, x=1 is a zero.
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Answer: a 
You are correct
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Cheers,
stan H.