Question 21755
Label the rectangluar prism.
|AD| = 6N
|AB|=15N
|AE|=10N
|AG|=Endpoint
|AG|^2=5^2+10^2+15^2
simplify |AG|=19N   <GBA = cosine (alpha) =15/19 /// {{{alpha}}}=38degrees /// <EAG = cosine (beta) =10/19 /// beta=58degrees
Hence, the resultant force is 19N making an angle of 38 and 58 degrees

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