Question 144089
C=pi*diameter
thus pi*d=5
and d=5/pi

d^2 will be the area of the square.
d^2=25/(pi)^2

Now, pi*r^2=Area of circle

and r=1/2d=(1/2)(5/pi)=(5/(2pi))

Thus, A= pi*(25/(4pi^2))=25/(4pi)

The left over area will be 5/(pi)^2-25/(4pi).