Question 143980
let x be the side of the smallest field. It's area is x^2
The next field is (x+1)^2 = x^2 + 2x + 1
The bi field is (x+3)^2 = x^2 + 6x + 9

The total is 38

{{{38 = x^2 + x^2 + 2x + 1 + x^2 + 6x + 9}}}
{{{0 = 3x^2 + 8x - 28}}}
{{{0 = (3x+14)(x-2)}}}

x = -14 or x =2

Since the field cannot be less than 0, x must be 2.
the next field is 3 and the big one is 5.

Does 5^2 + 3^3 + 2^2 = 38?