Question 143925

{{{h(x)=x^2+23x+60}}} Start with the given equation



{{{h(x)=x^2+23x+60}}} Plug in {{{h(x)=0}}}



{{{0=(x+20)(x+3)}}} Factor the right side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x+20=0}}} or  {{{x+3=0}}} 


{{{x=-20}}} or  {{{x=-3}}}    Now solve for x in each case



So our answers are


 {{{x=-20}}} or  {{{x=-3}}}