Question 143893
log2(x - 2) + 5 = 8 - log2 4
log2(x-2)+log2(4) = 8-5
log2[4(x-2)] = 3
4(x-2) = 2^3
4x-8 = 8
4x = 16
x = 4
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Cheers,
Stan H.