Question 143855

{{{3x^2-41x=-60}}} Start with the given equation



{{{3x^2-41x+60=0}}}  Add 60 to both sides. 



{{{(x-12)(3x-5)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x-12=0}}} or  {{{3x-5=0}}} 


{{{x=12}}} or  {{{x=5/3}}}    Now solve for x in each case



So our answers are 


 {{{x=12}}} or  {{{x=5/3}}}