Question 143852
{{{y=x+5}}} Start with the second equation



{{{(1/5)x+10=x+5}}} Plug in {{{y=(1/5)x+10}}} (ie replace y with {{{(1/5)x+10}}})



{{{(5)((1/5)x+10)=(5)(1x+5)}}} Multiply both sides by the LCM of 5. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{x+50=5x+25}}} Distribute and multiply the LCM to each side




{{{x=5x+25-50}}}Subtract 50 from both sides



{{{x-5x=25-50}}} Subtract 5x from both sides



{{{-4x=25-50}}} Combine like terms on the left side



{{{-4x=-25}}} Combine like terms on the right side



{{{x=(-25)/(-4)}}} Divide both sides by -4 to isolate x




{{{x=25/4}}} Reduce



So the first part of our answer is {{{x=25/4}}}




{{{y=(1/5)x+10}}} Go back to the first equation



{{{y=(1/5)(25/4)+10}}} Plug in {{{x=25/4}}}



{{{y=25/20+10}}} Multiply



{{{y=5/4+10}}} Reduce



{{{y=45/4}}} Add




So the second part of our answer is {{{y=45/4}}}




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Answer:


So our solutions are {{{x=25/4}}} and {{{y=45/4}}}