Question 143625
write the first five terms of the sequence

T<sub>1</sub> = 1, T<sub>n</sub> = 2T<sub>n-1</sub> + 2

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You already have T<sub>1</sub>, so you replace n by 2, 
then by 3, then by 4, then by 5.

T<sub>n</sub> = 2T<sub>n-1</sub> + 2

Replacing n by 2:

T<sub>2</sub> = 2T<sub>2-1</sub>+2 = 2T<sub>1</sub>+2 = 2(1)+2 = 2+2 = 4

Replacing n by 3:

T<sub>3</sub> = 2T<sub>3-1</sub>+2 = 2T<sub>2</sub>+2 = 2(4)+2 = 8+2 = 10

Replacing n by 4:

T<sub>4</sub> = 2T<sub>4-1</sub>+2 = 2T<sub>3</sub>+2 = 2(10)+2 = 20+2 = 22

Replacing n by 5:

T<sub>5</sub> = 2T<sub>5-1</sub>+2 = 2T<sub>4</sub>+2 = 2(22)+2 = 44+2 = 46

and the sequence is

T<sub>1</sub>, T<sub>2</sub>, T<sub>3</sub>, T<sub>4</sub>, T<sub>5</sub>

or  1, 4, 10, 22, 46

Edwin</pre>