Question 143704
P(Ace first, Queen second, given that the card is NOT replaced)= {{{(4/52)*(4/51)}}}={{{(1/13)*(4/51)= 4/663}}}, since on the second draw there are only 51 cards left in the deck.


By contrast, if the first card is replaced, then there are still 52 to choose from on the second draw:
P(Ace first, Queen second, given that the card IS replaced)= {{{(4/52)*(4/52)}}} = {{{ (1/13)*(1/13)=1/169}}}.


As a check, I calculated the decimal equivalents and the first answer came out approximately .0060, while the second answer came out about .0059.  As you should expect, these are very close, but the second slightly less, since there were more cards to choose from on the second draw.  (Just an after thought!! gnore this last paragraph if it confused anyone!!)


R^2