Question 143607
Let's write symbols for the three numbers:
n1=x
n2=(x+1)
n3=(x+2)

So, we want 3n1=3x to be 4 more than 2n2=2(x+1)

Which is:
3x=2(x+1)+4
3x=2x+6
x=6.

This is the first number. The second number is x+1=6+1=7.
So the numbers are 6 and 7.

check:
3*6=18
2*7=14
18-14=4!