Question 143606
1. If you are unsure of anything I did, I will be happy to iterate the steps I took. E-mail me at enabla@gmail.com
-6/x - 3/x^2 = 2 
-6-3/x=2x
-3/x=2x+6
-3=2x^2+6x
0=2x^2+6x+3

Now use the quadratic formulae:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}.
*[invoke quadratic "x", 2, 6, 3 ]
2. Notice the parentheses I put and make sure that it is correct.
- 6/x + 6/(x+9) = 1
-6+6x/(x+9)=x
6x/(x+9)=x+6
6x=(x+6)(x+9)
6x=x^2+15x+54
0=x^2+9x+54

Again, use the quadratic formulae.
*[invoke quadratic "x", 1, 9, 54 ]