Question 143541
"The tank has a height of 6m and a diameter of 10 m" __ 6/10=H/(2r) __ 12r=10H __ r=(5/6)H


V=(1/3)(pi)(r^2)(H) __ substituting __ V=(1/3)(pi)[(5/6)H]^2(H) __ V=(25/108)(pi)(H^3)


differentiaitng __ dV=(25/108)(pi)(3)(H^2)(dH) __ dV=(25/36)(pi)(H^2)(dH)


let x="rate at which the water is being pumped into the tank" __ working in cm


x-10000=(25/36)(pi)(200^2)(20) __ x=1.76X10^6cm^3/min (approx)