Question 143484
Vertex--> x= -b/2a  for quadratic equation in form ax^2+bx+c=0. 

Axis of symmetry--> in general the x value of the vertex.

Max/min--> Without the use of calculus, we can notice that this will be a parabola that opens DOWNWARD (leading term, a, is negative), thus the vertex has to be the maximum.

In order to graph, find the intercepts by setting g(x)=0, then find the y-intercept by setting x=0. You have essentially all the information, now, to produce this:


{{{graph( 300, 300, -5, 5, -30, 30, -2x^2 + 2x +1 )}}}

If you want me to go more in-depth send me an E-mail at enabla@gmail.com .