Question 143312

AT LEAST YOU TRIED BUT THE PROBLEM IS ASKING FOR A NUMBER (HOW MANY DIMES?)-NOT AN AMOUNT.


Let x=number of nickels
And let y=number of dimes
Now, we are told the following ($ understood):

0.05x+0.10y=5.65-----------------------------------------eq1

and

0.05(x+8)+0.10*2y=10.45 simplify

0.05x+0.4+0.20y=10.45  subtract 0.4 from each side

0.05x+0.20y=10.05---------------------------------------eq2

subtract eq1 from eq2 and we get:
0.10y=4.40  divide each side by 0.10

y=44--------------------------------------number of dimes

substitute y=44 into eq1

0.05x+0.10*44=5.65
0.05x+4.40=5.65  subtract 4.40 from each side
0.05x=1.25  divide each side by 0.05
x=25---------------------------------------------number of nickels

CK

25*0.05+44*0.10=5.65
1.25+4.40=5.65
5.65=5.65
and
0.10*88+0.05*33=10.45
8.80+1.65=10.45
10.45=10.45

Hope this helps-----ptaylor