Question 143331


{{{x^2+2x+2b+bx}}} Start with the given expression



{{{x^2+2x+bx+2b}}} Rearrange the terms



{{{(x^2+2x)+(bx+2b)}}} Group like terms



{{{x(x+2)+b(x+2)}}} Factor out the GCF {{{x}}} out of the first group. Factor out the GCF {{{b}}} out of the second group



{{{(x+b)(x+2)}}} Since we have the common term {{{x+2}}}, we can combine like terms



{{{(x+b)(x+2)=0}}} Set the expression equal to zero






Now set each factor equal to zero:


{{{x+b=0}}} or  {{{x+2=0}}} 


Now solve for x for each factor:


{{{x=-b}}} or  {{{x=-2}}}