Question 143291
Given square ABCD with AB= 2x+1 and CD= 5x-19 what is the perimeter of the square?
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All the sides are equal so:
2x+1 = 5x-19
3x = 20
x = 20/3
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One of the sides is 2x+1 = 2(20/3)+1 = 43/3
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The perimeter = 4(43/3) = 172/3 = 57 1/3
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Cheers,
Stan H.