Question 143227
Yes, 'that rise over run stuff' will work just fine in this case.  You can also select a different value for x (4 would work out quite neatly) and then calculate the resulting y.  This would give you a second point, (4, whatever y turns out to be).  Plot that point and then draw your line through the two points.


Letting x = 0, then solve for y (which is the same thing as examining the 'b' part of {{{y=mx+b}}}, by the way) and then letting y = 0 and solving for x is a perfectly legitimate way to find two points that define a line.  But there is no reason (other than simplification of the arithmetic) that you need to find the intercept points specifically.  You can select any value you like for x and then solve for y.  The only thing you need to remember is that you need to find 2 points somewhere to define a straight line.