Question 143185
Okay, let "x" be the number or score that Jason needs for the fifth project so he can have an average of at leat 85. To compute,
82+85+78+88+x=333+x, right? These are all his scores for the 5 projects. In order to get the average, we divide this by 5 and should equal to 85 right amigo? To show,
(333+x)/5 = 85   -------------------- eqn 1
solving for "x" thereafter,
333+x=85*5
x=425-333
x= 92.This should be his final score on the last project, what do you think?
In doubt?
 Go back eqn 1, 
(333+92)/5 = 85,   cool!
Thank you,
Jojo